Unit 54 further controlSystemsControl and Representation of Mechanical systems where: mkcF[kg]––mass(stiffness)coefficientbody[N/m][Ns/m]––[N]thespringconstantdampingexternalforceactingon x [m] – displacement of the bodyOur mechanical system consists in a translational inertial element, compliant element and resistive element.Free Body Diagram (FBD)• Drawing the FBD means representing all the forces acting on each mass of the system.Translational mass with spring-damper (FBD)• When applying … Continue reading “further control Systems | My Assignment Tutor”
Unit 54 further controlSystemsControl and Representation of Mechanical systems where: mkcF[kg]––mass(stiffness)coefficientbody[N/m][Ns/m]––[N]thespringconstantdampingexternalforceactingon x [m] – displacement of the bodyOur mechanical system consists in a translational inertial element, compliant element and resistive element.Free Body Diagram (FBD)• Drawing the FBD means representing all the forces acting on each mass of the system.Translational mass with spring-damper (FBD)• When applying an external force F to the body there will be opposite forces which willtry to keep the body in the same place. These forces are:• elastic force Fe [N] – it is generated by the spring• inertial force Fi [N] – it is generated by the mass• damping force Fd [N] – it is generated by the viscous friction • Using Laplace transform of the above equation:FL-kX(S)-cSX(S)-mS2 X(S) =0 (1)if initial values of x(0) and x'(0) are zeros and F = F(t) and FL is Laplace transform of F(t)• Rearrange the above equation (1) to get the transfer function of the system TF(s):FL=kX(S)+cSX(S)+mS2 X(S)TF(s)= X(s) /FL = 1/ (k+cS+mS2) (2)• Then you apply step input to obtain the response of the system which is represented bythe transfer function; you can use MATLAB or simulink to simulate /to control thesystem using open loop and closed loop system.END
