bution =-1.75 6) The probability that lies between 1.10 and 0.3 D) 0.4951 mally distribut Provide an appropriate response 7) Find the area of the shaded rion. The y distributed with a mean of 100 anda e d region. The graph s of adults, and those scores are of 100 and a standard deviation of 15s on the Wechsler test) A) 0.7436 B) 0.6293 C) 0.8051 D) 0.4100 8) Find the e area of the shaded region. The graph depicts scores of adults, and the scores ale may distributed with a mean of 100 and a standard deviation of 15 (as on the Wechsler ). 5 3 0 DO 130 135 DOIS 140 DS A) 0.7938 B) 0.7303 C) 0.7745 D) 0.7619 ) 9) Find the indicated I score. The graph depicts I scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15 (as on the Wechsler test). The shaded area under the curve is 0.10. B) 10.1 A) 80.8 C) 1192 D) 100.5 10) Solve the problem. Round to the nearest tenth unless indicated otherwise. 10) In one region, the September energy consumption levels for single-family homes are found to be normally distributed with a mean of 1050 kWh and a standard deviation of 218 kWh. Find P45. which is the consumption level separating the bottom 45% from the top 55%. A) 1087.8 B) 1021.7 C) 1148.1 D) 1078.3