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Fe2O3(s) + 2Al(s)Al2O3(s) + 2Fe(s) for which H° = -851.5 kJ and S° = -37.00 J/K…
Fe2O3(s) + 2Al(s)Al2O3(s) + 2Fe(s) for which H° = -851.5 kJ and S° = -37.00 J/K at 298.15 K.
(1) Calculate the entropy change of the UNIVERSE when 2.413 moles of Fe2O3(s) react under standard conditions at 298.15 K. S universe = J/K
(2) Is this reaction reactant or product favored under standard conditions? (
3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy?
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