In an addition reaction of an alkene or alkyne, a reactant, such as bromine (Br2Br2), hydrogen (H2H2), or water (H2OH2O), is added to the two atoms that form the multiple bond.

When there is a triple bond, the first equivalent is added to form a new bond at each atom of the multiple bond, and the species formed has a double bond. The second equivalent will again add to the two atoms that form the multiple bond, and an alkane is formed, as shown:

CH3C≡CCH3+Cl2→ClCl|  | CH3C=CCH3+Cl2→ClCl|  |CH3C−CCH3|  |ClClClClClCl|  | |  |CH3C≡CCH3+Cl2→CH3C=CCH3+Cl2→CH3C−CCH3|  |ClCl

For this problem, draw all hydrogen atoms explicitly.

Part A

Draw the product of the reaction

CH3CH2CH2CH2C≡CCH3+2Br2→?CH3CH2CH2CH2C≡CCH3+2Br2→?

Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. Include all hydrogen atoms.

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Submit

Part B

What is the name of the product of the hydrogenation of 3,6,6-trimethyl-4-nonene?

Enter the name of the compound.

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