A genetic experiment involving peas yielded one sample of offspring consisting of 434 green peas and 137 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 25% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? OA. O B. Ho: p 0.25 H: p>0.25 D. Ho:p#0.25 H: p 0.25 F. Ho :p#0.25 H: p0.25 ° C. H0: p = 0.25 What is the test statistic? (Round to two decimal places as needed) What is the P-value? P-value Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a B. Reject the null hypothesis because the P-value is less than or equal to the significance level, α. O C. Reject the null hypothesis because the P-value is greater than the significance level, a. D. Fail to reject the null hypothesis because the P-value is greater than the significance level, «. What is the final conclusion? ○ A. There is not sufficient evidence to warrant rejection of the claim that 25% of offspring peas will be yellow. There is sufficient evidence to warrant rejection of the claim that 25% of offspring peas will be yellow. There is sufficient evidence to support the claim that less than 25% of offspring peas will be yellow. There is not sufficient evidence to support the claim that less than 25% of offspring peas will be yellow. B. c. D.