Assignment 3: Independent sampled T test
Directions
Conduct an Independent Samples T test to answer the questions based on the following scenario. (Assume a non-directional research hypothesis (two-tailed test) and a level of significance of .05)
Scenario
The superintendent who collected data for Assignments 1 and 2, continued to examine the district’s data. One question that concerned the superintendent’s constituencies was the difference between the school performance scores of the superintendent’s district and a neighboring district that had similar demographic and socio-economic characteristics. The superintendent collected the following information:
School performance scores for superintendent’s district:
102 | 101 | 82 | 101 | 104 | 81 | 76 | 60 | 68 | 102 | 101 | 102 | 86 | 106 |
81 | 99 | 73 | 90 | 107 | 80 | 84 | 96 | 106 | 99 | 96 |
School performance scores for comparison district:
99 | 77 | 91 | 74 | 89 | 96 | 87 | 84 | 81 | 70 | 105 | 86 | 105 | 77 |
93 | 91 | 72 | 98 | 94 | 87 | 79 | 80 | 106 | 86 | 87 | 79 | 91 |
Questions
- What are the mean and standard deviation for the superintendent’s district?
Mean = 90.4091
Standard deviation = 13.54590
- What are the mean and standard deviation for the comparison district?
Mean = 87.5556
Standard deviation = 9.98204
- State an appropriate null hypothesis for this analysis.
Null Hypothesis: There is no difference between the school performance scores of the superintendent’s district and a neighboring district that had similar demographic and socio-economic characteristics.
- What is the observed or computed value of t?
1.010
- What is the value of the degrees of freedom that are reported in the output (equal variances assumed)?
21
- What is the reported level of significance?
0.324
- Based on the reported level of significance, would you reject the null hypothesis?
No, I would not reject as the level of significance is greater than 95% confidence interval.