1MIS501 Principles of ProgrammingAssessment 2 – Business Case StudyCase ScenarioCOMP101 Foundations of Computer Systems is a first-year introductory subject in both the Bachelorof Information Technology and Diploma of Information Technology course at ABC University. TheSubject Coordinator of COMP101 has engaged you to help her to code a few Python programs ashandy tools to solve a number of problems at hand.Task 1 – Determine Interim Grade Letter (30%)In this task, you will write a Python program to help the Subject Coordinator of COMP101 to calculatean interim grade letter for a student given their assessments results.COMP101 Foundations of Computer Systems has three assessments with the following weightings. Assessment NumberAssessment TypeAssessment Weighting1Lab exercise20%2Report40%3Final examination40% Each assessment has been marked out of 100 and the mark for each assessment may be a decimalnumber with at most two decimal points (e.g., 68, or 68.5, or 68.45). The final mark for COMP101 isthe weighted sum of all three assessments, rounded up 1to the nearest integer. For example, StudentA received 75.67/100, 45.8/100, 32/100 for Assessment 1, 2 and 3 respectively. Their final mark forCOMP101 is 47 (46.254 rounded up to the nearest integer).75.67 × 20% + 45.8 × 40% + 32 × 40% = 46.254For simplicity, in this Task, we will use a bracket that consists of three numbers to denote the marksof a student’s three assignments in order. For example, (75.67, 45.8, 32) denote a student whoreceived 75.67/100 for the first assessment, 45.8/100 for the second, and 32/100 for the third.The final mark is used to determine the interim grade letter for a student. The Assessment Policy andProcedures of ABC University stipulates the following rules for determining the interim grade letter.The range in the Final mark column includes the numbers on both ends. Final markInterim grade letterDescription85 – 100HDHigh Distinction75 – 84DDistinction65 – 74CCredit50 – 64PPass45 – 49F or SE or SAFail or Supplementary Assessment or Supplementary Exam0 – 44F or AFFail or Absent Fail 1 No students like their marks rounded down, so always round up their marks. Even if the weighted sum is 90.001, theirfinal mark should be recorded as 91.2Students whose final mark is between 0 and 44 (inclusive) may be awarded an F (Fail) or an AF (AbsentFail). If two or more assessments are awarded zero and the final mark is between 0 and 44 (inclusive),the student will be awarded an AF (Absent Fail), otherwise they are awarded an F (Fail).For example, students with (0, 100, 0) should be awarded an AF because their final mark is 40, andtwo assessments are marked zero. However, students with (100, 50, 0) should be awarded an Fbecause although their final mark is 40, they only have one assessment awarded zero.Students who have marginally failed, that is, their final mark is between 45 – 49 (inclusive), may beawarded an F (Fail) or Supplementary Exam (SE) or Supplementary Assessment (SA). If a student’s finalmark is between 45 – 49, they will receive an F (Fail) unless they satisfy all the following conditions:o Their final mark is between 45 – 49 (inclusive).o They do not have any assessment marked zero.o They only failed (i.e., less than 50) one assessment.Students whose final mark is between 45 – 49 will receive an SE or SA if they satisfy all the conditionsabove. If the assessment they failed is Assessment 1 or Assessment 2, they will receive an SA and theywill be given an opportunity to attempt a supplementary assessment. If the assessment they failed isAssessment 3, they will receive an SE and they will be given an opportunity to sit a supplementaryexam.For example, students with (40, 100, 0) will receive an F (Fail) because although their final mark is 48(i.e., between 45 – 49), they have one assessment marked zero (Assessment 3). Students with (10,100, 10) will equally be awarded an F (Fail) because although their final mark is 46 (i.e., between 45 –49), they have failed more than one assessment (Assessment 1 and Assessment 3). Students with (50,50, 40) will be awarded an SE because their final mark is 46 (i.e., between 45 – 49) and satisfy all thethree conditions above. The only failed assessment is Assessment 3, and they will be given anopportunity to sit a supplementary exam.The Subject Coordinator has asked you to develop a Python program that can calculate the interimgrade letter for a student given the marks for all the assessments based on the business rulesdescribed above.Your program should allow the Subject Coordinator to type in a student’s assessment marks separatedby a comma. Your program will then output the correct interim grade letter for that student. In thistask, you do not need to allow the Subject Coordinator to type in the assessment marks for anotherstudent. Your program can terminate after it have calculated and output the interim grade letter forthe first student.Here are some sample inputs and outputs the Subject Coordinator expected to see when she runsyour program. All the green lines are your program outputs, all the red lines are users’ input.Sample input and output 1: Enter a student’s assessment marks (separated by comma): 40,100,0 FSample input and output 2: Enter a student’s assessment marks (separated by comma): 90,100,1003 HDSample input and output 3: Enter a student’s assessment marks (separated by comma): 50,50,40 SEImplement your program in a Python script file and name it task1.py. You need to submit this fileas part of the Assessment 2 submission.Task 2 – Finalising grades and class performance statistics (40%)This task is built upon Task 1. You may want to make a copy of task1.py, and name it task2.py,and you may want to use the logic you implemented for Task 1. DO NOT override task1.py.A couple of weeks after the Release of Grade date, all supplementary assessments and exams havebeen finalised. All the interim grade letters now need to be converted to a final grade letter, that is,the grade letter that appear on students’ transcript.For HD (High distinction), D (Distinction), C (Credit), P (Pass) and F (Fail), they will not be converted asthey themselves are final grade letters. For SA and SE, they will be converted to either a SP(Supplementary Pass) or F (Fail). If the student who have been awarded an SA or SE, passed thesupplementary assessment or supplementary exam (that is, they achieved no less than 50/100), theirgrade letter will be converted to SP (Supplementary Pass), otherwise it will be converted to F (Fail).For AF (Absent Fail), it will be converted to F (Fail).Each final grade letter carries some grade point value as detailed in the table below. Final grade letterGrade point valueHD4.0D3.0C2.0P1.0SP0.5F0 The Subject Coordinator would like you to implement a Python program that helps her to read in allstudents’ marks and generate some high-level statistic about the class performance.InputIn contrast with Task 1, the program in Task 2 will prompt to the Subject Coordinator (the user) andallow her type in all students’ assessment marks. This is achieved by repeatedly asking the SubjectCoordinator to type in students’ three assessment marks until she types in the letter “N”. For example, Enter a student’s assessment marks (separated by comma), type in letter N to finish: 40,100,0 Enter a student’s assessment marks (separated by comma), type in letter N to finish: 90,100,100 Enter a student’s assessment marks (separated by comma), type in letter N to finish:4 N(input finishes)The Subject Coordinator (the user) may type in as many students’ assessment marks as she wishes.Each line of input represents a student’s three assessment marks. The only way she signals to theprogram that she has done with inputting is to type in a letter N.Your program should use an appropriate data structure to store students’ marks.As you read in students’ assessment marks, if your program detects that the student would have beengiven an SE or SA, your program should then ask for their supplementary assessment orsupplementary exam mark. For example, Enter a student’s assessment marks (separated by comma), type in letter N to finish: 40,100,0 Enter a student’s assessment marks (separated by comma), type in letter N to finish: 50,50,40 What is this student’s supplementary exam mark: 67 Enter a student’s assessment marks (separated by comma), type in letter N to finish: 90,100,100 Enter a student’s assessment marks (separated by comma), type in letter N to finish: N(input finishes)OutputAfter input finishes, your program will then output the following class performance statistics:o Number of students: This number shows the total number of students that the user typed in.o Student pass rate: The percentage of students who received a final grade letter of HD, D, C, Por SP, that is,#???????? + #???? + #???? + #???? + #????????#????????????????????????????#HD represents the number of students who received HD. #student represents the totalnumber of students. Rounded to two decimal points.o Student pass rate (adjusted): The percentage of students who received a final grade letter ofHD, D, C, P or SP. This percentage excludes students who received an AF from the total numberof students, that is,#???????? + #???? + #???? + #???? + #????????#???????????????????????????? – #????????Rounded to two decimal points.o Average mark for Assessment 1: the average mark for Assessment 1 with two decimal points.o Average mark for Assessment 2: the average mark for Assessment 2 with two decimal points.o Average mark for Assessment 3: the average mark for Assessment 3 with two decimal points.o Average final mark: the average mark for final mark with two decimal points.5o Average grade point: the average grade point for all students in COMP101 with one decimalpoint.o Number of HDs: the number of students who received a final grade letter HD.o Number of Ds: the number of students who received a final grade letter D.o Number of Cs: the number of students who received a final grade letter C.o Number of Ps: the number of students who received a final grade letter P.o Number of SPs: the number of students who received a final grade letter SP.o Number of Fs: the number of students who received a final grade letter F.For example, Enter a student’s assessment marks (separated by comma), type in letter N to finish: 40,100,0 Enter a student’s assessment marks (separated by comma), type in letter N to finish: 50,50,40 What is this student’s supplementary exam mark: 67 Enter a student’s assessment marks (separated by comma), type in letter N to finish: 90,100,100 Enter a student’s assessment marks (separated by comma), type in letter N to finish: N Number of students: 3 Student pass rate: 66.67% Student pass rate (adjusted): 66.67% Average mark for Assessment 1: 60.00 Average mark for Assessment 2: 83.33 Average mark for Assessment 3: 46.67 Average final mark: 64.00 Average grade point: 1.5 Number of HDs: 1 Number of Ds: 0 Number of Cs: 0 Number of Ps: 0 Number of SPs: 1 Number of Fs: 1Implement your program in a Python script file and name it task2.py. You need to submit this fileas part of the Assessment 2 submission.6Task 3 – Naïve similarity detector (30%)This task is independent of the first two tasks. You can create a new file and name it task3.py.The Subject Coordinator of COMP101 has now asked you to implement a naïve similarity detector thatshe can use to identify collusion between students in their assessments. Your program will read in twoassessment submissions (two strings) in turn and output a similarity score for them.You can assume that the input submissions have been “cleaned” with all punctuations removed. Eachsubmission is a sequence of words separated by a space. For example,“COMP101 is an interesting subject and it has been easy”“COMP101 and COMP301 have always been interesting and easy”The similarity of two submissions is defined as the ratio between the number of common words inboth submissions and the number of unique words in both submissions.For example,“COMP101 is an interesting subject and it has been easy”“COMP101 and COMP301 have always been interesting and easy”The common words between these two submissions are COMP101, and, interesting, been, easy. Atotal of 5 common words.The unique words in both submissions are COMP101, and, interesting, been, easy, is, an, subject, it,has, COMP301, have, always. A total of 13 common words.The similarity of both submissions is 5/13 = 38.46%.You are required to draw a flowchart diagram illustrating the logic of this program. You should use aprofessional drawing software, e.g. http://draw.io. Copy and paste your flowchart diagram in aMSWord document, and name it task3.docx.Implement a Python program that takes in two submissions (strings) and output the similaritybetween them with two decimal points. For example: Enter the first submission: COMP101 is an interesting subject and it has been easy Enter the second submission: COMP101 and COMP301 have always been interesting and easy The similarity score between the two is: 38.46%.You should ignore the letter cases, that is, “Interesting” and “interesting” should be treated as thesame word. You do not need to lemmatise the words, that is, the words “going”, “go”, “went”, “gone”are treated as different words.You must not use the set structure in this or any other tasks. 0 marks will be awarded to theimplementation if you used the set structure.Implement your program in a Python script file and name it task3.py. You need to submit this fileas part of the Assessment 2 submission.
