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Convert the binding constants to dissociation constants and give the pKa,A for each dissociation constant.

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(a) Write the binding polynomial for ATP at 298.15K in terms of binding constants in the absence of Mg for application between 3 <>c < 14.=”” assume=”” ideal=”” solutions.=”” hint:=”” use=”” untransformed=”” equilibrium=”” constants=”” calculated=”” from=”” the=”” gibbs=”” energies=”” of=”” formation,=”” and=”” ignore=”” the=”” species=”” that=”” don’t=”” have=”” gibbs=”” energies=”” tabulated=”” in=”” the=”” appendix.=””>

(b) Convert the binding constants to dissociation constants and give the pKa,A for each dissociation constant.

(c) Using the binding constants, calculate and plot the vs. pH for ATP between 3 <>c < 14.=”” mark=”” the=””> at the pKa,A values determined in (b).

(d) Give the fraction of each species at a pHc = 7.6.

 

 

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